SOLUTION: using a system of equations to solve the applied problem. Solve the system Ten liters of 30% solution needs to be mixed with 80% solution to produce a 50 % solution. How much of th

Question 476652: using a system of equations to solve the applied problem. Solve the system Ten liters of 30% solution needs to be mixed with 80% solution to produce a 50 % solution. How much of the 80% solution is needed. I need this by 2pm

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Ten liters of 30% solution needs to be mixed with 80% solution to produce a 50 % solution.
How much of the 80% solution is needed.
:
Let x = amt of 80% solution
:
you can solve this with a single equation using the decimal equiv of per cent;
:
.30(10) + .80x = .50(x + 10)
3 + .80x = .50x + 5
.80x - .50x = 5 - 3
.30x = 2
x =
x = 6 liters of 80% solution required
:
:
:
Check this decimals
.3(10) + .8(6.67) = .50(6.67+10)
3 + 5.333 = .50(16.67)
8.333 ~ 8.335

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