Hi,
Now that I am understanding Your question properly:
Mixing 2m^3 of 35% solution with 6m^3 of 15% solution
Generally, recommend letting x represent a 'decimal value' on the right side
Mixing
.35*2m^3 + .15*6m^3 = x* 8m^3
1.6m^3 = x*8m^3
1.6/8 = x
.20 = x |.20 = 20/100 OR 20% |Converting the decimal to Percent
mixing will result in 8m^3 of 20% Solution
If I am understanding Your Question properly: disregard
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x = 1280m^6