SOLUTION: A lab assistant is asked to mix a 30% alcohol solution with 21 liters of an 80% alcohol solution to make a 60% alcohol solution. How many liters of the 30% alcohol solution should

Question 474192: A lab assistant is asked to mix a 30% alcohol solution with 21 liters of an 80% alcohol solution to make a 60% alcohol solution. How many liters of the 30% alcohol solution should be used?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Let x represent the amount of the 30% solution

MIXING

 .30x + .80*21L = .60(x+21L)

          .20*21L = .30x

                 x = .20*23L/.3 = 14L, the amount of the 30% solution



 

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