SOLUTION: How many liters of pure water must be added to 6 liters of a 30% solution to get a 10% solution

Question 472081: How many liters of pure water must be added to 6 liters of a 30% solution to get a 10% solution
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of pure water must be added to 6 liters of a 30% solution to get a 10% solution
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Equation:
water + water = water
x + 0.70*6 = 0.90(x+6)
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Multiply thru by 100 to get:
100x + 70*6 = 90x + 90*6
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10x = 20*6
x = 3 liters (amt. of pure water needed)
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Cheers,
Stan H.
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