Hi,

Mixing TO GET 8 L OF A FERTILIZER 

Let x and (8L-x) represent the amount of the 12% and the 8% respectively

Question states***

Mixing to form 8 L OF A FERTILIZER CONTAINING 11% NITROGEN

 .12x + .08(8-x) = .11*8L

     .04x = .88 - .64  Will let You finish it Up 

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