Hi,

mixed to get 20 gallons

Let x and (20-x) represent the amount of the  35% and 25% solutions respectively

Question states*** 

 mixing to get 20 gal of 32% alcohol

   .35x + .25(20-x) = .32*20G

Solving for x

     .10x  = .07*20G =  

      x = 14G, the amount of the 35% Solution.  6G of the 25% solution



CHECKING our Answer***

.35*14 + .25*6  = 4.9 + 1.5 = .32*20 = .64 

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