SOLUTION: Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol?

Question 468154: Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol?
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Equation:
alcohol + alcohol = alcohol
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0.10x + 0.90(80-x) = 0.35*80
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Multiply thru by 100 to get:
10x + 90*80 - 90x = 35*80
-70x = -55*80
x = (8/7)*55
x = 62.86 quarts (amt. of 10% solution needed)
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80-x = 80-62.86 = 17.14 quarts (amt. of 90% solution needed)
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Cheers,
Stan H.
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