SOLUTION: How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Use 6 step method.
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Question 467444: How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Use 6 step method.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
----------- percent ---------------- quantity
Antifreeeze I 25 ---------------- 70 L
Antifreeze II 60 ---------------- x L
Total 50 ---------------- 70 + x L
25*70+60*x=50(70+x)
1750+60x=3500+50x
60x-50x=3500-1750
10x=1750
/10
x=175 L 60 % Antifreeze II
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