SOLUTION: How many milligrams of pure water must be added to 6 mg of a 40% solution to obtain a 25% solution? Round to the nearest tenth.

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many milligrams of pure water must be added to 6 mg of a 40% solution to obtain a 25% solution? Round to the nearest tenth.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 463751: How many milligrams of pure water must be added to 6 mg of a 40% solution to obtain a 25% solution? Round to the nearest tenth.
Answer by jorel1380(2518) About Me  (Show Source):
You can put this solution on YOUR website!
6x.4=2.4
.25p=2.4
p=2.4/.25=9.6
9.6-6=3.6 gms pure water necessary to be added..