SOLUTION: How many milligrams of pure water must be added to 6 mg of a 40% solution to obtain a 25% solution? Round to the nearest tenth.
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Question 463751: How many milligrams of pure water must be added to 6 mg of a 40% solution to obtain a 25% solution? Round to the nearest tenth.
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
6x.4=2.4
.25p=2.4
p=2.4/.25=9.6
9.6-6=3.6 gms pure water necessary to be added..
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