SOLUTION: How many gallons of 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70%antifreeze?
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Question 462040: How many gallons of 80% antifreeze solution must be mixed with 100 gallons of 10% antifreeze to get a mixture that is 70%antifreeze?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
.8n+100(.1)=.7(n+100)
.8n+10=.7n+70
.1n=60
n=60/.1=600
You need 600 gallons of 80% antifreeze for your mix.
.8(600)+100(.1)=480+10=490
.7(600+100)=.7(700)=490..
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