SOLUTION: A druggist wants to reduce a 20-ounce quantity of a 7% solution of iodine to a 4% solution by adding pure alcohol. How much alcohol must he add to accomplish this?

Algebra.Com
Question 456726: A druggist wants to reduce a 20-ounce quantity of a 7% solution of iodine to a 4% solution by adding pure alcohol. How much alcohol must he add to accomplish this?
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
20(.93)+n=.96(20+n)
18.6+n=19.2+.96n
.04n=.06
n=.6/.04=15
You need 15 ozs. of pure alcohol for your mix..

RELATED QUESTIONS

A druggist wants to reduce a 20-ounce quantity of a 7% solution of iodine to a 4%... (answered by josmiceli)
A pharmacist has 4 quarts of a 15% solution of iodine. How much alcohol must be added to... (answered by Alan3354)
A chemist has 40 ounces of a solution of iodine and alcohol, which is 15% iodine. How... (answered by mananth)
A chemist has 40 ounces of a solution of iodine and alcohol that is 15% iodine. How much... (answered by lwsshak3)
A Chemist has a mixture that is 10% iodine and another that is 50% iodine. How much of... (answered by stanbon,oberobic)
How much pure water must be mixed with 15 ounce of a 30% alcohol solution to obtain a 25% (answered by josmiceli)
how many ounce of a 15% alcohol solution nmust bemixed with 4 ounces of a 20 % alcohol... (answered by stanbon)
how much alcohol in pints must be added to 80 pints of a solution of alcohol and iodine... (answered by nerdybill)
how much pure alcohol should be added to 24 ounce of a 45% solution in order to obtain... (answered by Fombitz)