SOLUTION: pure acid is to be added to a 20% solution to obtain 60 liters of a 30% acid solution. what amounts of each should be used?

SOLUTION: pure acid is to be added to a 20% solution to obtain 60 liters of a 30% acid solution. what amounts of each should be used?

Algebra.Com

Question 451435: pure acid is to be added to a 20% solution to obtain 60 liters of a 30% acid solution. what amounts of each should be used?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
1.00x + 0.20(60-x) = 0.30*60
==> x + 12 - 0.20x = 18
==> 0.80x = 6
==> x = 7.5 liters of pure acid, and
60 - x = 52.5 liters of the 20% acid.
RELATED QUESTIONS
Pure acid is to be added to a 5% acid solution to obtain 95L of 30% solution. What... (answered by stanbon)

Pure acid is to be added to a 10% acid solution to obtain 54L of a 20% acid solution.... (answered by longjonsilver)

pure acid is to be added to a 20% acid solution to obtain 40L of a 40% acid solution.... (answered by josgarithmetic)

Pure Acid is to be added to a 10% acid solution to obtain 27 litters of 20% acid... (answered by robertb)

Pure acid is to be added to a 5% acid solution to obtain 95 liters of 14% solution. What... (answered by Alan3354)

Pure acid is to be added to a 10% acid solution to obtain 90 L of a 20% acid solution.... (answered by josgarithmetic)

Pure acid is to be added to a 10% acid solution to obtain 90 L of a 20% acid solution.... (answered by Alan3354)

Pure acid is to be added to a 10% acid solution to obtain 81 L of a 20% acid solutions.... (answered by ankor@dixie-net.com)

Pure acid is to be added to a 5% acid solution to obtain 95L of 44% solution. What... (answered by jorel1380)