SOLUTION: A.Find the equation of the quadratic function in standard form vertex (0, 18) ; passing through (-3, 0) A. y = -2x2 + 18 B. y = -2x2 - 18 C. y = x2 + 18 D. y = 18x2

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Question 440161: A.Find the equation of the quadratic function in standard form
vertex (0, 18) ; passing through (-3, 0)
A. y = -2x2 + 18
B. y = -2x2 - 18
C. y = x2 + 18
D. y = 18x2 + 18
B. 6. Write the quadratic function in the vertex form.
y = -3x^2 - 30x - 71
A. y = 3(x + 5) 2 + 4
B. y = -3(x - 5) 2 + 4
C. y = (x + 5) 2 + 4
D. y = -3(x + 5) 2 + 4



Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
Using the vertex form of a parabola, where(h,k) is the vertex
vertex (0, 18)
y = ax^2 + 18 |passing through (-3, 0)
0 = a*9 + 18
-18 = 9a
-2 = a
y = -2x^2 + 18
Write the quadratic function in the vertex form.
y = -3x^2 - 30x - 71 |Completing the square to do so
y = -3[x^2 +10x] - 71
y = -3[(x+5)^2 -25] - 71
y = -3(x+5)^2 + 75 - 71
y = -3(x+5)^2 + 4


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