SOLUTION: how much water should be mixed with 6 gallons of 30% alcohol to get a 20% alcohol solution

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Question 431443: how much water should be mixed with 6 gallons of 30% alcohol to get a 20% alcohol solution
Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
6 gallons of 30% alcohol=1.8 gallons of pur alcohol--
.20*x gallons=1.8
x=1.8/.2=9 gallons
Since you already have 6 gallons, you need 3 gallons of pure water to thin the mix down to 20%..
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