SOLUTION: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced?

Question 424443: A chemist mixes distilled water with a 90 % solution of sulfuric acid to produce a 50% solution. If 5 liters of distilled water are used, how much 50% solution is produced?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
90% sulfuric acid=10% water
.90m+5(1.00)=.5(m+5)
.90m+5=.5m+2.5
.4m=2.5
m=2.5/.4=6.25
You started with 6.25 liters of 90% solution. Add the 5 liters of distilled water, and you have 11.25 liters of a 50% solution..
RELATED QUESTIONS
A chemist mixes distilled water with a 90% solution of sulfuric acid to produce a 50%... (answered by ptaylor)

A chemist mixes distilled water with a 90% solution of sulfuric acid to produce a 50%... (answered by josgarithmetic)

A chemist mixes distilled water with a 85 percent solution of sulfuric acid to produce a... (answered by TimothyLamb)

A Chemist mixes distilled water with 70% solution of sulfuric acid to produce a 30%... (answered by josmiceli)

Can you please help me solve this? A chemist wants to mix distilled water with a 75%... (answered by ankor@dixie-net.com)

A student mixes distilled water with a 90% solution of acid to produce a 50% solution. If (answered by stanbon)

how many liters of distilled water must be added to 80% liters of 60% acid solution to... (answered by Alan3354)

How many ounces of 35% solution of sulfuric acid(and distilled water) must be mixed with... (answered by checkley77)

A 96% solution of sulfuric acid is to be diluted with distilled water to make a 90%... (answered by ankor@dixie-net.com)