# SOLUTION: a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with 20% solution. How many gallons of each solution is needed?

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 Click here to see ALL problems on Mixture Word Problems Question 423721: a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with 20% solution. How many gallons of each solution is needed?Answer by mananth(12269)   (Show Source): You can put this solution on YOUR website!percent ---------------- quantity 12 ---------------- x 20 ---------------- 100-x Total18.00%--------------100 ...... 12x+20(100-x)=18*100 12x+2000 -20x=1800 12x-20x= 1800-2000 -8x=-200 /-8 x=25 liters of 12.00% 75 liters of 20.00%