SOLUTION: a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with 20% solution. How many gallons of each solution is needed?
Algebra.Com
Question 423721: a lab needs to make 100 gallons of a 18% acid solution by mixing a 12% acid solution with 20% solution. How many gallons of each solution is needed?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
12 ---------------- x
20 ---------------- 100-x
Total18.00%--------------100 ......
12x+20(100-x)=18*100
12x+2000 -20x=1800
12x-20x= 1800-2000
-8x=-200
/-8
x=25 liters of 12.00%
75 liters of 20.00%
RELATED QUESTIONS
A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid solution (answered by checkley79)
A lab needs to make 100 gallons of an 18% acid solution by mixing a 12% acid
solution... (answered by stanbon,josgarithmetic)
A lab needs to make 500 gallons of a 34% acid solution. The only solutions available are (answered by lwsshak3)
a lab needs to make 100 gallons of an 18% acis solution by mixing a 12% acid solition... (answered by josmiceli)
A CHEMIST NEEDS TO MIX AN 18% ACID SOLUTION WITH A 45% ACID SOLUTION TO OBTAIN 12 GALLONS (answered by josmiceli)
How many gallons of a 25% acid solution must be mixed with 100 gallons of a 6% acid... (answered by stanbon)
2. 15 gallons of a 20% acid solution is to be mixed with a 12% acid solution to yield an (answered by ankor@dixie-net.com)
how many gallons of a 20% acid solution must be mixed with 6 gallons of a 30% acid... (answered by KnightOwlTutor)
How many gallons of a solution of 20% acid must be blended with a solution of 5% acid to... (answered by ewatrrr)