SOLUTION: what are the x and y intercepts of the line defined by -8x + 6y = -48

Question 423242: what are the x and y intercepts of the line defined by -8x + 6y = -48
Found 2 solutions by rfer, oberobic:
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
6y=8x-48
y=8/6x-8
y int=(0,-8)
x int=(6,0)
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
First, get the equation into slope-intercept form.
-8x +6y = -48
Add 8x to both sides.
6y = 8x -48
Divide both sides by 6
y = (8/6)x - 8
.
The x-intercept is where y=0, so substitute y=0.
0 = (8/6)x - 8
Add 8 to both sides.
8 = (8/6)x
(8/6)x = 8
Multiply both sides by 6.
8x = 48
Divide both sides by 8
x = 6
.
So the x=intercept is (6,0).
.
The y-intercept is where x=0.
.
y = (8/6)x - 8
Substitute x=0
y = -8
.
So the y-intercept is (0,-8).
.
Always check your answer.
In this case a graph is useful.
.

.
Looks good.
Done.
.
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