SOLUTION: a merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of mixture worth $2.10 per pound. how many pounds of each should be used

Question 421152: a merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of mixture worth $2.10 per pound. how many pounds of each should be used?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=amount of jelly beans needed
Then 30-x=amount of peanuts needed
Now we know that the total value of the peanuts and jelly beans before the mixture takes place has to equal the value of the final mixture.
Value of peanuts and jelly beans before the mixture takes place ($ understood):
1.50x+3(30-x)
Value of the final mixture:
2.10*30
So our equation to solve is:
1.50x+3(30-x)=2.10*30 simplify
1.50x+90-3x=63 subtract 90 from each side and collect like terms
-1.50x=-27
x=18 lb----------------amount of jelly beans needed
30-x=30-18=12 lb---------------amount of peanuts needed
CK
18*1.50+12*3=2.10*30
27+36=63
63=63
Hope this helps---ptaylor

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