SOLUTION: the original mixture weighed 800 pounds and was 40% slaked lime. how much of a 20% slaked lime mixture sh9ould be added to reduce the lime concentration to 36%?
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Question 418776: the original mixture weighed 800 pounds and was 40% slaked lime. how much of a 20% slaked lime mixture sh9ould be added to reduce the lime concentration to 36%?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
800(.4)+m(.2)=.36(800+m)
320+.2m=288+.36m
32=.16m
m=200
You need 200 lbs of 20% lime to reduce your concentration..
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