SOLUTION: combine an alloy that costs $4.30 and ounce with an alloy that cost $1.80 an ounce. Hou many ounces of each were used to make a mixture of 200 ounces costing $2.50 per ounce?

Question 416360: combine an alloy that costs $4.30 and ounce with an alloy that cost $1.80 an ounce. Hou many ounces of each were used to make a mixture of 200 ounces costing $2.50 per ounce?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = ounces of $4.30/oz alloy needed
Let = ounces of $1.80/ oz alloy needed
In words:
(cost of 1st alloy + cost of 2nd alloy) / (total ounces of both) = cost/ounce
(1)
(2)
-----------------
(1)
(1)
(1)
-----------------
Multiply both sides of (2) by and
subtract from (1)
(1)
(2)

and,

56 ounces of $4.30/oz alloy are needed
144 ounces of $1.80/ oz alloy are needed
check answer:
(1)
(1)
(1)

OK
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