# SOLUTION: Hi! I have a problem that has stumped me. Here it is: A nurse has 2 solutions that contain different concentrations of a certain medication. One is a 12% concentration, and t

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Hi! I have a problem that has stumped me. Here it is: A nurse has 2 solutions that contain different concentrations of a certain medication. One is a 12% concentration, and t      Log On

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 Question 414970: Hi! I have a problem that has stumped me. Here it is: A nurse has 2 solutions that contain different concentrations of a certain medication. One is a 12% concentration, and the other is an 8% concentration. How many cubic centimeters (cc) of each should she mix together to obtain 20 cc of a 9% solution. So far, I started something like this: .12x + .08x = 20(.09), but not sure that is right and don't know how to plug back into problem to get the concentrations. THANK YOU SO MUCH!!Answer by ankor@dixie-net.com(16524)   (Show Source): You can put this solution on YOUR website!A nurse has 2 solutions that contain different concentrations of a certain medication. One is a 12% concentration, and the other is an 8% concentration. How many cubic centimeters (cc) of each should she mix together to obtain 20 cc of a 9% solution. : Let's do it this way : Let x = amt of 12% concentration It say's the result is to be 20 cc, therefore (20-x) = amt of 8% concentration : A typical mixture equation: .12x + .08(20-x) = .09(20) .12x + 1.6 - .08x = 1.8 .12x - .08x = 1.8 - 1.6 .04x = .2 x = x = 5 cc of 12% concentration then 20 - 5 = 15 cc of 8% ; : Check this .12(5) + .08(15) = .09(20) .6 + 1.2 = 1.8; confirms our solution