SOLUTION: We have a 20% alcohol solution and 50% alcohol solution. How many pints must be used from each to obtain 8 pints of a 30% solution?

Question 412860: We have a 20% alcohol solution and 50% alcohol solution. How many pints must be used from each to obtain 8 pints of a 30% solution?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
20 ---------------- x
50 ---------------- 8-x
30.00% ---------------- 8
..
20x+50(8 -x)=30*8
20x+400- 50x=240
20x-50x =240-400
-30x=-160
/-30
x=5.33 20% alcohol
Balance 2.67 50% alcohol

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