# SOLUTION: How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution?

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 Question 412260: How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution?Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution? ------ Equation: active + active = active 0.20*12 + 1.00x = 0.50(12+x) --- Multiply thru by 100 to get: 20*12 + 100x = 50*12 + 50x 50x = 30*12 ---- x = (3/5)12 x = 36/5 x = 7 1/5 gallons (amt. of pure antifreeze needed) ================== Cheers, Stan H. ==============