SOLUTION: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the orginal solution must be drained off and replaced by pure antifreeze to make a 25% soluti

Question 408969: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the orginal solution must be drained off and replaced by pure antifreeze to make a 25% solution of antifreeze?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

Let x represent the amount drained off and replaced

Question states***

  .20(16qt-x) + 1*x = .25*16qt

Solving for x

   .8x = .05*16qt

     x = 1qt, needs to be drained off and replaced with pure antifreeze



CHECKING our Answer***

  .20*15 + 1 =  4 = .25*16 

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