Hi

combine to obtain 12 liters

Let x and (12L-x) represent the amount of %14 and %8 solution respectively

Question states***

 .14x + .08(12L-x) = .10*12L

Solving for x

    .06x = .02*12L

       x = 4L, the amount of 14% solution.  8L of 8% solution.  (12L-4L)



CHECKING our Answer***

  .14*4L + .08*8L = .56L + .64L = 1.2L 

RELATED QUESTIONS

How much water must be added to 14 liters of a 90% acid solution to obtain a 40% acid... (answered by richwmiller)

A chemist has 10% and 50% solutions of acid available. How many liters of each solution... (answered by solver91311)

How many liters each of 12.5% acid solution and 20.25% acid solution must be mixed to... (answered by stanbon)

Solution A is 25% acid and Solution B is 10% acid. How many liters of each must be mixed... (answered by Alan3354)

Mr. Samuel has a 10% solution of hydrochloric acid and a 50% solution of hydrochloric... (answered by checkley71)

How much 20% acid solution and 80% acid solution should be combined to obtain 100 liters... (answered by josmiceli)

A chemist has only 50% and 20% sulfuric acid on his laboratory. How much of each should... (answered by gwendolyn)

A lab has a 20% acid solution and a 50% acid solution. How many liters of each are... (answered by nerdybill)

A chemist needs 10 L of a solution that is 35% acid. In his lab, he has a supply of a 45%  (answered by josgarithmetic)