SOLUTION: Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liters of each solution should be mixed to make 4.5 liters of a 40%-alcohol solut

Question 408907: Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liters of each solution should be mixed to make 4.5 liters of a 40%-alcohol solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

Let x and (4.5-x)represent the amount of the 50% and 20% solution respectively

Question states***

  .50x + .20(4.5 -x) = .40*4.5L

Solving for x

     .30x = .20*4.5L

Will let You finish it up 

RELATED QUESTIONS

Suppose that one solution contains 50% alcohol and another solution contains 90% alcohol.  (answered by scott8148)

Suppose that one solution contains 20% alcohol and another solution contains 50%... (answered by checkley79)
Suppose that one solution contains 40% alcohol and another solution contains 80% alcohol.  (answered by Boreal)
Suppose that one solution contains 40% alcohol and another solution contains 80% alcohol.  (answered by ikleyn,amalm06)
Suppose that one solution contains 30% alcohol and another solution contains
80%... (answered by greenestamps,Edwin McCravy)
One solution contains 20% alcohol and another solution contains 60% alcohol. Some of each  (answered by josgarithmetic,MathTherapy,amalm06)
One solution contains 50% alcohol and another solution contains 80% alcohol. How many... (answered by John10,josmiceli)
One solution contains 50% alcohol and another solution contains 80% alcohol. How many... (answered by josmiceli)
Please help me solve the story problem : One solution contains 50% alcohol and another... (answered by nerdybill)