SOLUTION: A 40% saline solution is to be mixed with a 60% saline solution to obtain 8 liters of a 55% saline solution. How many liters of each solution should be used?

Question 408138: A 40% saline solution is to be mixed with a 60% saline solution to obtain 8 liters of a 55% saline solution. How many liters of each solution should be used?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi

Let x and (8L-x)represent the amounts of the 60% and 40% solutions respectively

Question states***

 .60x + .40(8L-x) = .55*8L

Solving for x

       .20x =  .15*8L  x = 6L, amount of 60%,  2L of 40%.  (8L-6L)

CHECKING our Answer***

  .6*6 + .4*2 = 4.4 = .55*8 

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