SOLUTION: How many liters of a 40% alcohol solution must be mixed with a 60 L of a 80% solution to get a 50% solution?

Question 406204: How many liters of a 40% alcohol solution must be mixed with a 60 L of a 80% solution to get a 50% solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 40% alcohol solution must be mixed with a 60 L of a 80% solution to get a 50% solution?
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Equation:
alco + alco = alco
0.80*60 + 0.40x = 0.50(60+x)
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Multiply by 100 and solve for "x":
80*60 + 40x = 50*60 + 50x
-10x = -30*60
x = (1/3)*60
x = 20L (amt. of 40% solution needed)
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Cheers,
Stan H.
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