SOLUTION: If you have 12 liters of antifreeze at a 40% solution how many liters do you need to add to increase the percentage to 60%? The answer is 6 but how do you write it correctly in alg

Question 405149: If you have 12 liters of antifreeze at a 40% solution how many liters do you need to add to increase the percentage to 60%? The answer is 6 but how do you write it correctly in algebra?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If you have 12 liters of antifreeze at a 40% solution how many liters do you need to add to increase the percentage to 60%?
:
Let x = amt of pure antifreeze to get a 60% solution
:
.40(12) + x = .60(x+12)
4.8 + x = .6x + 7.2
x - .6x = 7.2 - 4.8
.4x = 2.4
x =
x = 6 liters
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