SOLUTION: A 3% solution of sulfuric acid was mixed with an 18% solution of sulfuric acid to produce an 8% solution. How much 3% and how much 18% solution were used to produce 15L of 8% solut
Algebra.Com
Question 399640: A 3% solution of sulfuric acid was mixed with an 18% solution of sulfuric acid to produce an 8% solution. How much 3% and how much 18% solution were used to produce 15L of 8% solution?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.18x+.03(15-x)=.08*15
.18x+.45-.03x=1.2
.15x=1.2-.45
.15x=.75
x=.75/.15
x=5 L of 18% solution is used.
15-5=10 L of 3% solution is used.
Proof:
.18*5+.03*10=.08*15
.90+.30=1.20
1.20=1.20
RELATED QUESTIONS
A 3% solution of sulfuric acid was mixed with an 18% solution to produce an 8% solution.... (answered by checkley77)
A 2% solution of sulfuric acid was mixed with a 12% solution of sulfuric acid to produce... (answered by richwmiller)
How many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by nerdybill)
how many liters of a 40% sulfuric acid solution should be mixed with 4 liters of a 24%... (answered by mananth)
A chemist wants to make a 45% solution of Sulfuric Acid more concentrated by addingpure... (answered by josmiceli)
A 50%sulfuric acid solution is to be mixed with a 75% sulfuric acid solution to get 60... (answered by josmiceli)
I need help solving this word problem.
A chemist mixed 3 liters of 30% sulfuric acid... (answered by josmiceli)
A chemist mixed 3 liters of 30% sulfuric acid with a sample of 80% sulfuric acid to... (answered by checkley79)
Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to... (answered by Alan3354)