SOLUTION: The radiator in a car is filled with a solution of 70% antifreeze and 30% water. The manufacturer of the antifreeze suggests that, for summer driving, optimal cooling of the engine
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Question 397865: The radiator in a car is filled with a solution of 70% antifreeze and 30% water. The manufacturer of the antifreeze suggests that, for summer driving, optimal cooling of the engine is obtained with only 60% antifreeze. If the capacity of the radiator is 3.5 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The radiator in a car is filled with a solution of 70% antifreeze and 30% water.
The manufacturer of the antifreeze suggests that, for summer driving, optimal
cooling of the engine is obtained with only 60% antifreeze.
If the capacity of the radiator is 3.5 L, how much coolant should be drained
and replaced with water to reduce the antifreeze concentration to the recommended level?
:
let x = amt to be removed, also = the amt of water to be added
:
We can do this equation using per cent water
:
70% antifreeze is 30% water
60% antifreeze is 40% water
:
.30(3.5-x) + x = .40(3.5)
1.05 - .3x + x = 1.36
-.3x + x = 1.26 - 1.05
.7x = .31
x =
x ~ .443 liters removed and .443 liters of water added
;
:
Check solution using percent antifreeze
.7(3.5-.443) = .6(3.5)
.7(3.057) = 2.1
2.14 ~ 2.10
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