SOLUTION: A guy has five rings, each weighing 11 g, made of an alloy of 15% silver and 85% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 55%. Ho

Question 397861: A guy has five rings, each weighing 11 g, made of an alloy of 15% silver and 85% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 55%. How much silver should he add?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A guy has five rings, each weighing 11 g, made of an alloy of 15% silver and 85% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 55%. How much silver should he add?
:
Total weight: 5 * 11 = 55 grams
:
Let s = amt of silver required
When 55% gold is obtained, silver content will be 45%
:
Write a percent silver equation
.15(55) + s = .45(s+55)
8.25 + s = .45s + 24.75
s - .45s = 24.75 - 8.25
.55s = 16.5
s =
s = 30 grams of silver to be added
:
:
Check
.15(55) + 30 = .45(30 + 55)
8.25 + 30 = .45(85)
38.25 = 38.5, confirms our solution of 30 grams of silver
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