SOLUTION: How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
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Question 396802: How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
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Equation:
acid + acid = acid
1*x + 0.15*150 = 0.25(x+150)
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Multiply thru by 100 to get:
100x + 15*150 = 25x + 25*150
75x = 10*150
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x = 20 mL (amount pure acid needed for the mixture)
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Cheers,
Stan H.
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