# SOLUTION: A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which w

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which w      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Mixtures Solvers Lessons Answers archive Quiz In Depth

 Question 393357: A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which will be 66% gold? Answer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which will be 66% gold? ------------ Equation: gold + gold = gold 0.70x + 0.60(100-x) = 0.66*100 --- Multiply thru by 100 to get: 70x + 60*100 - 60x = 66*100 10x = 6*100 x = 60 oz (amt. of 70% alloy needed in the mix) --- 100-x = 40 oz (amt of 60% alloy needed in the mix) ============== Cheers, Stan H.