SOLUTION: Pure Acid is to be added to a 10% acid solution to obtain 27 litters of 20% acid solution. What amounts of each should be used?

SOLUTION: Pure Acid is to be added to a 10% acid solution to obtain 27 litters of 20% acid solution. What amounts of each should be used?

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Question 385899: Pure Acid is to be added to a 10% acid solution to obtain 27 litters of 20% acid solution. What amounts of each should be used?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Let x = # liters of pure acid that had to be added. Then
Then x + 0.10(27- x) = 0.20*27;
x + 2.7 - 0.10x = 5.4;
0.90x = 2.7;
x = 3 liters of pure acid.
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