SOLUTION: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 80% acid solution?

Question 380613: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 80% acid solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi,

Let x represent the amount of the 100% pure acid solution

1.00x + .40*2gal = .80*(x + 2gal)

solving for x

.20x = .40*2gal

x = 4 gal of pure acid needed.



CHECKING our Answer

4 + .8 = 4.8 = .8*6 

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