SOLUTION: How much pure acid should be mixed with 4 gallons of a 60% acid solution in order to get a 80% acid solution?

Question 380612: How much pure acid should be mixed with 4 gallons of a 60% acid solution in order to get a 80% acid solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi,

Let x represent the amount of the 100% pure acid solution

1.00x + .60*4gal = .80*(x + 4gal)

solving for x

.20x = .20*4gal

x = 4 gal of pure acid needed.



CHECKING our Answer

4gal + 2.4gal = 6.4gal = .8*8gal = 6.4gal 

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