SOLUTION: How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get a 90% acid solution?

Question 380610: How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get a 90% acid solution?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi,

Let x represent the amount of the 100% pure acid solution

1.00x + .10*6gal = .90*(x + 6gal)

solving for x

.10x = .80*6gal

x = 48 gal of pure acid needed.



CHECKING our Answer

48gal + .6gal = 48.6gal = .9*54gal = 48.6gal 

RELATED QUESTIONS

How much pure acid should be mixed with 6 gallons of a 20% acid solution in order to get... (answered by edjones)
How much pure acid should be mixed with 2 gallons of an 80% acid solution in order to get  (answered by oberobic)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by stanbon)
How much pure acid should be mixed with 2 gallons of a 60 percent acid solution in order... (answered by stanbon)
How much pure acid should be mixed with 5 gallons of a 70% acid solution in order to get... (answered by mananth)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by josmiceli)
How much pure acid should be mixed with 5 gallons of a 40% acid solution in order to get... (answered by josmiceli)
	
How much pure acid should be mixed with 2 gallons of a 60% acid solution in order to... (answered by addingup,josmiceli)
How much pure acid should be mixed with 2 gallons of a 30% acid solution in order to get... (answered by Fombitz)