Hi,

Let x represent the amount of the more concentrated 20% solution

then (10L-x) would be the amount of the 15% solution

Mixing to form a 17% 10L solution***Amount of acid in each the equalizer

.20*x + .15(10L -x) = .17*10L

solving for x

.20*x + .15*10L -.15x = .17*10L

.05x = .02*10L

x = .02*10L/.05

x = 4L, the amount of the 20% solution.  

6L the amount of the 15% solution (10L-4L)

CHECKING our Answer

.20*4L + .15*6L = .8L + .9L = 1.7L = .17*10L

 

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