SOLUTION: how many liters of a 20% alcohol solution must be mixed with 30 liters of a 80% solution to get a 40% solution?
Algebra.Com
Question 373503: how many liters of a 20% alcohol solution must be mixed with 30 liters of a 80% solution to get a 40% solution?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
0.20x + 0.80*30 = 0.40(x + 30),
0.20x + 24 = 0.40x + 12,
12 = 0.20x,
x = 60, #liters of 20% alcohol solution that must be added.
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