SOLUTION: A dehydrated patient needs a 6.4% saline IV. Unfortunately, the hospital only has bags of 6% and 8% saline solutions. How many liters of each of these solutions should be mixed tog

Algebra.Com
Question 372670: A dehydrated patient needs a 6.4% saline IV. Unfortunately, the hospital only has bags of 6% and 8% saline solutions. How many liters of each of these solutions should be mixed together to yield 1 liter of the desired concentration?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x represent the amount of the 8% solution,
then (1L-x) would be the amount of the 6% solution
.08x + .06(lL -x) = .064*1L
solving for x
.08x + .06*1L - .06x = .064*1L
.02x = .004L
x = .2L of the the 8% solution and .8L of the 6% solution (1L-.2L)

RELATED QUESTIONS

A dehydrated patient needs a 6.4% saline IV. Unfortunately, the hospital only has bags... (answered by Fombitz)
A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of (answered by nerdybill)
A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags of (answered by ankor@dixie-net.com)
A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags... (answered by mananth)
A dehydrated patient needs a 2.6% saline IV. Unfortunately, the hospital only has bags of (answered by josmiceli)
A dehydrated patient needs a 3.6% saline IV. Unfortunately, the hospital only has bags of (answered by sofiyac,mananth)
A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags... (answered by ewatrrr)
A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags of (answered by stanbon)
A dehydrated patient needs a 3.82% saline IV. Unfortunately, the hospital only has bags... (answered by lwsshak3)