SOLUTION: A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed
Algebra.Com
Question 371779: A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed
Answer by amoresroy(361) (Show Source): You can put this solution on YOUR website!
A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed
Let x = the number of milliliters of 30% needed
100-x = the number of milliliters of 50% needed
0.30x + 0.50(100-x) = .35(100)
0.30x + 50 - 0.5x = 35
-0.2x = 35-50
x = 75
75 milliliters of 30% are needed
RELATED QUESTIONS
How many liters of a 30% acid solution should be mixed with an 80% acid solution to get... (answered by ewatrrr)
How many ounces of a 35% acid solution should be mixed with a 60% acid solution to get 40 (answered by mananth,ikleyn)
how many liters of a 50% acid solution must be mixed with a 30% acid solution to get 200... (answered by mananth)
How many liters of a 50% acid solution must be mixed with a 30% acid solution to get 180L (answered by mananth)
how many liters of 50% acid solution must be mixed with a 30% acid solution to get 180... (answered by mananth)
How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L... (answered by ewatrrr)
A 20% acid solution is to be mixed with a 50% acid solution in order to get 600 ounces of (answered by richwmiller)
how many milliliters of a 20% acid solution should be mixed with 50 ml of an 8% acid... (answered by josgarithmetic)
How many ounces each of a 20% acid solution and a 50% acid solution must be mixed... (answered by Alan3354,ikleyn,greenestamps)