SOLUTION: A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters will have to be drained and then replaced with pure anitfreeze if the resulting solution is t
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Question 366952: A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters will have to be drained and then replaced with pure anitfreeze if the resulting solution is to be 50 percent antifreeze?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters will have to be drained and then replaced with pure anitfreeze if the resulting solution is to be 50 percent antifreeze?
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Equation:
anti - anti + anti = anti
0.20*10 - 0.20x + 1.00x = 0.50*10
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Multiply thru by 100 to get:
20*10 - 20x + 100x = 50*10
80x = 30*10
x = 3.75 liters (amt. that must be removed and replaced)
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Cheers,
Stan H.
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