SOLUTION: how much pure acid should be mixed with 5 gallons of a 60% acid solution in order to get a 80% acid solution

Question 363589: how much pure acid should be mixed with 5 gallons of a 60% acid solution in order to get a 80% acid solution
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi, 

Let x represent the amount of pure acid added (note: that is an 100% solution)

.60*5gal + 1.00*x = .80(5gal + x)

solve for x

.20x = .20*5gal

x = 5 gal of pure acid needs to be added.



checking our answer

.60*5gal + 5gal =  3gal + 5gal = .80*10gal = 8 gal 

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