SOLUTION: A metallurgist needs to make 12.4 lb of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of ea

Question 363358: A metallurgist needs to make 12.4 lb of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with another metal that is 40% gold. How much of each should he use?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
0.60x + 0.40(12.4 - x) = 0.50*12.4,
0.60x + 4.96 - 0.40x = 6.2,
0.20x = 1.24,
x = 6.2. He has to mix 6.2 lb of the 60% gold alloy, and the same amount of the 40% gold alloy.
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