SOLUTION: A chemist wants to make 50 mL of a 17% acid solution by mixing a 13% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?

Question 363211: A chemist wants to make 50 mL of a 17% acid solution by mixing a 13% acid solution and an 18% acid solution. How many milliliters of each solution should the chemist use?
Found 2 solutions by Fombitz, checkley77:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let A be the amount of 13% solution, B the amount of 18% solution.
1.
.
.

2.
Multiply eq. 1 by (-13) and add to eq. 2,

ml
Then from eq. 1,

ml
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.18x+.13(50-x)=.17*50
.18x+6.5-.13x=8.5
.05x=8.5-6.5
.05x=2
x=2/.05
x=40 ml of 18% acid is used.
Proof:
.18*40+.13(50-40)=.17*50
7.2+.13*10=8.5
7.2+1.3=8.5
8.5=8.5

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