SOLUTION: how much of a 50% acid solution must be mixed with 30 gallons of a 19% acid solution to obtain a solution that is 40% acid?

Question 358715: how much of a 50% acid solution must be mixed with 30 gallons of a 19% acid solution to obtain a solution that is 40% acid?
Found 2 solutions by nyc_function, checkley77:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Here is your equation and you can then solve for x.

0.50x + 0.19(30) = 0.40(x + 30)

Can you finish?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.50X+.19*30=.40(30+X)
.50X+5.7=12+.40X
.50X-.40X=12-5.7
.10X=6.3
X=6.3/.10
X=63 GALLONS OF 50% ACID SOLUTION IS USED.
PROOF:
.50*63+.19*30=.40(30+63)
31.5+5.7=.40*93
37.2=37.2

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