SOLUTION: How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution?
Algebra.Com
Question 354378: How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35% solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40 liters of a 35%
---------------------
Equation:
acid + acid = acid
0.20x + 0.60(40-x) = 0.35*40
----
Multiply thru by 100 to get:
20x + 60*40 - 60x = 35*40
-40x = -25*40
x = 25 liters (amt. of 20% solution needed in the mixture)
----
Cheers,
Stan H.
RELATED QUESTIONS
How many liters of a 20% acid solution must be mixed with 15 liters of a 60% solution to... (answered by math_helper)
How many liters of a 20% acid solution must be mixed with a 60% solution to obtain 40... (answered by jorel555,Theo)
How many liters of a 20% acid solution must be mixed with a 40% acid solution in order to (answered by Alan3354)
How many Liters of a 50% alcohol solution must be mixed with 40 Liters to obtain a 60... (answered by ptaylor)
how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by checkley75)
how many liters of a 10% acid solution must be mixed with a 50% acid solution in order to (answered by Alan3354)
How many liters of a 20% acid solution must be mixed with a 50 % acid solution in order... (answered by stanbon)
How many liters of a 10% solution of acid should be mixed with 60% solution of acid to... (answered by ewatrrr)
how many liters of a 50% acid solution must be mixed with a 20% acid solution to get 270... (answered by mananth)